Saturday, September 16, 2006

Some question that may come out for the experiment design for chem

Ok, since xuan qi asked, and i can't msn nor call her (because she busted her bills) i'm just gonna state some ways of the question being phrase. From someone who's not as good (as kwek), here's some SUGGESTIONS (by that meaning i will not be held responsible if you wrote this and got it wrong) for the experiment design qns.


Example:

X Forms a compound of MHCO3 which decomposes on heating according to the following equation.

2MHCO3 -> M2CO3 + CO2 + H2O

Given a sample of MHCO3 and the usual apparatus (meaning no super advanced science invention that you can cock up and claim it exists) in a school laboratory, suggest an experiment(normally other then the one you do for titration) which could be use to find the atomic Mass of M. You should include measurements you would take and show how you would use your results to obtain a value for the relative atomic mass of M.

So the answer wld be sth like this since they already give you the equation:

Heat a known MASS(not sample) of MHCO3 and collect the VOLUME (don't use amount) of Carbon Dioxide gas produced using a GAS SYRINGE (remember to name your apparatus and please stop commenting on how poor the school is that it doesnt have one). Using Volume/24dm^3 = NO. of Mol, you can find the mol of MHCO3 should double the amount of carbon dioxide (due to the equation) So once you know the Mol of MHCO3 and you have the mass of it, you can find the relative atomic mass of M by Mass/Molar mass = Mol.

Points to note, always remember to use the MOL concepts, the equations given and that few experiments we do. Always compare the MOLs in the equation, then you can find your ans.

As for the design the experiment crap, it appears in many ways, such as if you get a mass, you just say you obtain the mass by mixing acid and sth, you dry the residue btw filter papers and weigh the mass of the residue. Then using Mass/molar mass = mol, you can find the mol and blah blah.

So yeah, good luck =)

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